sin^2x+sin^2(2x)=sin^2(3x)

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Solution for sin^2x+sin^2(2x)=sin^2(3x) equation: 


Simplifying
sin2x + sin2(2x) = sin2(3x)

Remove parenthesis around (2x)
in2sx + in2s * 2x = sin2(3x)

Reorder the terms for easier multiplication:
in2sx + 2in2s * x = sin2(3x)

Multiply in2s * x
in2sx + 2in2sx = sin2(3x)

Combine like terms: in2sx + 2in2sx = 3in2sx
3in2sx = sin2(3x)

Remove parenthesis around (3x)
3in2sx = in2s * 3x

Reorder the terms for easier multiplication:
3in2sx = 3in2s * x

Multiply in2s * x
3in2sx = 3in2sx

Add '-3in2sx' to each side of the equation.
3in2sx + -3in2sx = 3in2sx + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
0 = 3in2sx + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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